0.3-x^2=0.05

Solution for 0.3-x^2=0.05 equation:

0.3-x^2=0.05

We move all terms to the left:

0.3-x^2-(0.05)=0

We add all the numbers together, and all the variables

-1x^2+0.25=0

a = -1; b = 0; c = +0.25;
Δ = b2-4ac
Δ = 02-4·(-1)·0.25
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1}{2*-1}=\frac{-1}{-2}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1}{2*-1}=\frac{1}{-2}
=-1/2
$